What is the solution of the recurrence T(n) = 3T(n/2) + n ?AΘ(n log n)BΘ(n^(log₂3))CΘ(n²)DΘ(n) Correct answer: B ExplanationHere a = 3, b = 2 so n^(log₂3) ≈ n^1.58 dominates f(n) = n, and case 1 of the Master theorem gives Θ(n^(log₂3)). Join the discussion Report an error