Some chocolates were distributed among four friends A, B, C and D such that the respective ratio between the number of chocolates received… — Answer & Discussion

Some chocolates were distributed among four friends A, B, C and D such that the respective ratio between the number of chocolates received by A and C be 7:9. B got 29 chocolates more than that of A and D got 33 chocolates more than that of C. If B got 15 chocolates more than that of C, how many chocolates did D receive?

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CCommunity06 Apr 2019

Solution
Chocolates got by A = $7x$
Chocolates got by C = $9x$
Chocolates got by B = $7x + 29$
Chocolates got by D = $9x + 33$
Acc to ques,
=> $(7x + 29) - (9x) = 15$
=> $2x = 29 - 15 = 14$
=> $x = 7$
$\therefore$ Chocolates received by D
= $9 \times 7 + 33 = 63 + 33 = 96$

CCommunity20 Apr 2019