14 men can do a work in 18 days, 15 women can do a work in 24 days. If 14 men work for first three days and 10 women work after that for th…

Solution
Work done by 14 men in 1 day = $\frac{1}{18}$
Work done by 14 men in 3 days = $3 \times \frac{1}{18} = \frac{1}{6}$
Work done by 1 woman in 1 day = $\frac{1}{15 \times 24}$
Work done by 10 women in 3 days = $\frac{10 \times 3}{15 \times 24} = \frac{1}{12}$
Total work done = $\frac{1}{6} + \frac{1}{12} = \frac{1}{4}$
Remaining work = $1 - \frac{1}{4} = \frac{3}{4}$

Solution
Work done by 14 men in 1 day = $\frac{1}{18}$
Work done by 14 men in 3 days = $3 \times \frac{1}{18} = \frac{1}{6}$
Work done by 1 woman in 1 day = $\frac{1}{15 \times 24}$
Work done by 10 women in 3 days = $\frac{10 \times 3}{15 \times 24} = \frac{1}{12}$
Total work done = $\frac{1}{6} + \frac{1}{12} = \frac{1}{4}$
Remaining work = $1 - \frac{1}{4} = \frac{3}{4}$