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If μ is an averaging operator and δn is the nth central difference operator, then what is the value of μ2?

3752Medium DSSSB TGT Computer Science 0 replies 2 views
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If μ is an averaging operator and δn is the nth central difference operator, then what is the value of μ2?

  • Aμ2 = 1⁄4(δ2 + 4)
  • Bμ2 = 1⁄2(δ2 + 4)
  • Cμ2 = 1⁄4(δ2 + 6)
  • Dμ2 = 1⁄4(δ2 + 8)
Correct answer: A

Explanation

μ² = 1/4 (δ² + 4) is the standard relation between the averaging and central difference operators.
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