Question discussion

Newton–Raphson is applied to f(x) = x² − 10 with x₀ = 3 to approximate √10. What is x₁?

Correct answer: B

Explanation

x₁ = x₀ − f(x₀)/f′(x₀) = 3 − (9 − 10)/6 = 3 + 1/6 = 19/6 ≈ 3.1667.

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